b^2+b-10=62

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Solution for b^2+b-10=62 equation:


Simplifying
b2 + b + -10 = 62

Reorder the terms:
-10 + b + b2 = 62

Solving
-10 + b + b2 = 62

Solving for variable 'b'.

Reorder the terms:
-10 + -62 + b + b2 = 62 + -62

Combine like terms: -10 + -62 = -72
-72 + b + b2 = 62 + -62

Combine like terms: 62 + -62 = 0
-72 + b + b2 = 0

Factor a trinomial.
(-9 + -1b)(8 + -1b) = 0

Subproblem 1

Set the factor '(-9 + -1b)' equal to zero and attempt to solve: Simplifying -9 + -1b = 0 Solving -9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -1b = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -1b = 0 + 9 -1b = 0 + 9 Combine like terms: 0 + 9 = 9 -1b = 9 Divide each side by '-1'. b = -9 Simplifying b = -9

Subproblem 2

Set the factor '(8 + -1b)' equal to zero and attempt to solve: Simplifying 8 + -1b = 0 Solving 8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1b = 0 + -8 -1b = 0 + -8 Combine like terms: 0 + -8 = -8 -1b = -8 Divide each side by '-1'. b = 8 Simplifying b = 8

Solution

b = {-9, 8}

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